# leap year calc as a Ruby if statement
# (Yes, I know it can be done with one if statement, but this
# version shows nesting!)

year = ARGV[0].to_i

if year % 4 == 0 then
    if year % 100 == 0 then
        if year % 400 == 0 then
          puts true
        else
          puts false
        end
    else
        puts true
    end
else
    puts false
end